Using Drupal 7.19 with PostgreSQL 8.4.13 I often see following error messages:
ERROR: invalid input syntax for integer: "login.php" at character 429
STATEMENT: SELECT base.uid AS uid, base.name AS name, base.pass AS pass, base.mail AS mail, base.theme AS theme, base.signature AS signature, base.signature_format AS signature_format, base.created AS created, base.access AS access, base.login AS login, base.status AS status, base.timezone AS timezone, base.language AS language, base.picture AS picture, base.init AS init, base.data AS data
FROM
drupal_users base
WHERE (base.uid IN ('login.php'))
ERROR: invalid input syntax for integer: "viewonline.php" at character 429
STATEMENT: SELECT base.uid AS uid, base.name AS name, base.pass AS pass, base.mail AS mail, base.theme AS theme, base.signature AS signature, base.signature_format AS signature_format, base.created AS created, base.access AS access, base.login AS login, base.status AS status, base.timezone AS timezone, base.language AS language, base.picture AS picture, base.init AS init, base.data AS data
FROM
drupal_users base
WHERE (base.uid IN ('viewonline.php'))
ERROR: invalid input syntax for integer: "ucp.php" at character 429
STATEMENT: SELECT base.uid AS uid, base.name AS name, base.pass AS pass, base.mail AS mail, base.theme AS theme, base.signature AS signature, base.signature_format AS signature_format, base.created AS created, base.access AS access, base.login AS login, base.status AS status, base.timezone AS timezone, base.language AS language, base.picture AS picture, base.init AS init, base.data AS data
FROM
drupal_users base
WHERE (base.uid IN ('ucp.php'))
ERROR: invalid input syntax for integer: "index.php" at character 429
STATEMENT: SELECT base.uid AS uid, base.name AS name, base.pass AS pass, base.mail AS mail, base.theme AS theme, base.signature AS signature, base.signature_format AS signature_format, base.created AS created, base.access AS access, base.login AS login, base.status AS status, base.timezone AS timezone, base.language AS language, base.picture AS picture, base.init AS init, base.data AS data
FROM
drupal_users base
WHERE (base.uid IN ('index.php'))This is probably easy to fix (in PHP code?) - looks like a string is used instead of numerical index for that string - when constructing an SQL query (for some report?)
Thanks